64=160x-6x^2

Solution for 64=160x-6x^2 equation:

64=160x-6x^2

We move all terms to the left:

64-(160x-6x^2)=0

We get rid of parentheses

6x^2-160x+64=0

a = 6; b = -160; c = +64;
Δ = b2-4ac
Δ = -1602-4·6·64
Δ = 24064
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{24064}=\sqrt{256*94}=\sqrt{256}*\sqrt{94}=16\sqrt{94}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-160)-16\sqrt{94}}{2*6}=\frac{160-16\sqrt{94}}{12}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-160)+16\sqrt{94}}{2*6}=\frac{160+16\sqrt{94}}{12}
$